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Geometry | SAT - Wyatt's Notes

flowchart TD
A[Geometry] --> B[Key Concepts]
A --> C[Core Principles]
A --> D[Practical Applications]
B --> E[Fundamental definitions]
C --> F[Design patterns]
D --> G[Real-world usage]

SAT mathematics study notes - Geometry

  • Area Formulas: triangle = ½bh, rectangle = lw, circle = πr², trapezoid = ½(b₁+b₂)h
  • Volume Formulas: rectangular prism = lwh, cylinder = πr²h, sphere = ⁴⁄₃πr³
  • Pythagorean Theorem: a² + b² = c² for right triangles. Special triples: 3-4-5, 5-12-13, 8-15-17.
  • Angle Relationships: vertical angles are equal, supplementary angles sum to 180°, complementary angles sum to 90°.
  • Coordinate Geometry: distance formula = √((x₂-x₁)² + (y₂-y₁)²), midpoint = ((x₁+x₂)/2, (y₁+y₂)/2)
  • Similar Triangles: proportional sides, equal angles. Scale factor k means area scales by k².
  • Circle Theorems: inscribed angle = ½ × central angle; tangent ⊥ radius.
ShapeAreaPerimeter/Circumference
Triangle12bh\frac{1}{2}bha+b+ca + b + c
Rectanglelwlw2l+2w2l + 2w
Circleπr2\pi r^22πr2\pi r
Trapezoid12(b1+b2)h\frac{1}{2}(b_1 + b_2)hsum of all sides
SolidVolumeSurface Area
Rectangular prismlwhlwh2(lw+lh+wh)2(lw + lh + wh)
Cylinderπr2h\pi r^2 h2πr2+2πrh2\pi r^2 + 2\pi rh
Sphere43πr3\frac{4}{3}\pi r^34πr24\pi r^2

Problem: A right triangle has legs of length 6 and 8. What is the length of the hypotenuse?

Solution: Step 1: Apply Pythagorean theorem: a² + b² = c² Step 2: 6² + 8² = 36 + 64 = 100 Step 3: c = √100 = 10

Key insight: 6-8-10 is a 3-4-5 triple scaled by 2. Memorising common triples (3-4-5, 5-12-13, 8-15-17) saves time.


Problem: A circle is inscribed in a 10 × 10 square. What is the area of the shaded region (square minus circle)?

Solution: Step 1: Square area = 10×10=10010 \times 10 = 100 Step 2: Circle diameter = 10, so radius = 5 Step 3: Circle area = π(5)2=25π78.54\pi(5)^2 = 25\pi \approx 78.54 Step 4: Shaded area = 10025π21.46100 - 25\pi \approx 21.46

Key insight: “Inscribed” means the circle touches all four sides — its diameter equals the square’s side length.


Problem: Triangle ABC has sides 3, 4, 5. Triangle DEF is similar with DE = 6. What is the area of DEF?

Solution: Step 1: Scale factor = DE/AB=6/3=2DE/AB = 6/3 = 2 Step 2: ABC is a right triangle (3² + 4² = 5²), area = 12(3)(4)=6\frac{1}{2}(3)(4) = 6 Step 3: Area scales by k2=4k^2 = 4, so DEF area = 6×4=246 \times 4 = 24

Key insight: When a shape is scaled by factor kk, area scales by k2k^2 and volume by k3k^3.


Geometry is the language of shapes and space. Angles are the conversation between lines — they tell you how steep a roof is or how sharp a turn is. Area is the amount of paint you would need to cover a surface; volume is the amount of water a container can hold. The Pythagorean theorem is the relationship between the sides of a right triangle — it tells you that if you know two sides, the third is determined. Coordinate geometry connects algebra to shapes, turning visual problems into equations you can solve. Transformations — rotations, reflections, translations — are like moving furniture in a room: the furniture stays the same, but its position changes.

Using the wrong formula for area vs perimeter. The area of a triangle is 12bh\frac{1}{2}bh while the perimeter is the sum of all sides. Students frequently use the perimeter formula when asked for area, or forget the 12\frac{1}{2} factor for triangles and trapezoids. Read the question carefully to determine which quantity is requested.

Confusing radius with diameter in circle problems. The SAT often provides the diameter when the formula requires the radius (or vice versa). The area of a circle is πr2\pi r^2, not πd2\pi d^2 or π(d/2)2\pi (d/2)^2 unless you explicitly substitute. Double-check whether the given measurement is radius or diameter before applying any formula.

Ignoring units in geometric measurements. When a problem gives dimensions in different units (feet and inches, or centimetres and metres), convert everything to the same unit before calculating. A common error is adding or comparing quantities with different units, such as computing area in “square feet and inches” instead of converting to a consistent unit first.

  • Algebra — Coordinate geometry combines algebraic equations with geometric shapes to solve problems involving lines and circles.
  • Data Analysis — Area and volume calculations appear in data interpretation questions involving real-world contexts.
  • Reading Comprehension — Visual information in passages such as maps and diagrams requires geometric reasoning.

This section provides detailed coverage of advanced concepts, including full derivations, proofs, and extended examples.

Complete mathematical derivations and proofs are provided where appropriate. Each step is explained to ensure understanding of the underlying reasoning.

Advanced examples demonstrate the application of concepts to complex problems. These examples go beyond standard exam questions to develop deeper understanding.

This material connects to current research and advanced applications in the field. Understanding these connections provides context for the study material.

Ensure you have mastered the prerequisite material before attempting this advanced content.

This section provides detailed coverage of advanced concepts, including full derivations, proofs, and extended examples.

Complete mathematical derivations and proofs are provided where appropriate. Each step is explained to ensure understanding of the underlying reasoning.

Advanced examples demonstrate the application of concepts to complex problems. These examples go beyond standard exam questions to develop deeper understanding.

This material connects to current research and advanced applications in the field. Understanding these connections provides context for the study material.

Ensure you have mastered the prerequisite material before attempting this advanced content.

This section provides detailed coverage of advanced concepts, including full derivations, proofs, and extended examples.

Complete mathematical derivations and proofs are provided where appropriate. Each step is explained to ensure understanding of the underlying reasoning.

Advanced examples demonstrate the application of concepts to complex problems. These examples go beyond standard exam questions to develop deeper understanding.

This material connects to current research and advanced applications in the field. Understanding these connections provides context for the study material.

Ensure you have mastered the prerequisite material before attempting this advanced content.